18p^2=24

Solution for 18p^2=24 equation:

18p^2=24

We move all terms to the left:

18p^2-(24)=0

a = 18; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·18·(-24)
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*18}=\frac{0-24\sqrt{3}}{36}
=-\frac{24\sqrt{3}}{36}
=-\frac{2\sqrt{3}}{3}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*18}=\frac{0+24\sqrt{3}}{36}
=\frac{24\sqrt{3}}{36}
=\frac{2\sqrt{3}}{3}
$